919. Complete Binary Tree Inserter 完全二叉树插入器
作者: 负雪明烛 id: fuxuemingzhu 个人博客: https://fuxuemingzhu.cn/
题目地址: https://leetcode.com/problems/complete-binary-tree-inserter/description/
A complete binary tree is a binary tree in which every level, except possibly the last, is completely filled, and all nodes are as far left as possible.
Write a data structure CBTInserter that is initialized with a complete binary tree and supports the following operations:
CBTInserter(TreeNode root)initializes the data structure on a given tree with head node root;CBTInserter.insert(int v)will insert a TreeNode into the tree with value node.val = v so that the tree remains complete, and returns the value of the parent of the inserted TreeNode;CBTInserter.get_root()will return the head node of the tree.
Example 1:
Input: inputs = ["CBTInserter","insert","get_root"], inputs = [[[1]],[2],[]]Output: [null,1,[1,2]]Example 2:
Input: inputs = ["CBTInserter","insert","insert","get_root"], inputs = [[[1,2,3,4,5,6]],[7],[8],[]]Output: [null,3,4,[1,2,3,4,5,6,7,8]]Note:
- The initial given tree is complete and contains between 1 and 1000 nodes.
- CBTInserter.insert is called at most 10000 times per test case.
- Every value of a given or inserted node is between 0 and 5000.
编写一个完全二叉树的数据结构,需要完成构建、插入、获取root三个函数。函数的参数和返回值如题。
周赛第三题,因为第二题我不会,就把这个题给放弃了……现在一看很简单啊。
完全二叉树是每一层都满的,因此找出要插入节点的父亲节点是很简单的。如果用数组tree保存着所有节点的层次遍历,那么新节点的父亲节点就是tree[(N -1)/2],N是未插入该节点前的树的元素个数。
构建树的时候使用层次遍历,也就是BFS把所有的节点放入到tree里。插入的时候直接计算出新节点的父亲节点。获取root就是数组中的第0个节点。
时间复杂度是O(N),空间复杂度是O(N)。
# Definition for a binary tree node.# class TreeNode(object):# def __init__(self, x):# self.val = x# self.left = None# self.right = None
class CBTInserter(object):
def __init__(self, root): """ :type root: TreeNode """ self.tree = list() queue = collections.deque() queue.append(root) while queue: node = queue.popleft() self.tree.append(node) if node.left: queue.append(node.left) if node.right: queue.append(node.right)
def insert(self, v): """ :type v: int :rtype: int """ _len = len(self.tree) father = self.tree[(_len - 1) / 2] node = TreeNode(v) if not father.left: father.left = node else: father.right = node self.tree.append(node) return father.val
def get_root(self): """ :rtype: TreeNode """ return self.tree[0]
# Your CBTInserter object will be instantiated and called as such:# obj = CBTInserter(root)# param_1 = obj.insert(v)# param_2 = obj.get_root()C++代码如下:
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class CBTInserter {public: CBTInserter(TreeNode* root) { queue<TreeNode*> q; q.push(root); while (!q.empty()) { TreeNode* node = q.front(); q.pop(); if (!node) continue; tree.push_back(node); q.push(node->left); q.push(node->right); } }
int insert(int v) { TreeNode* node = new TreeNode(v); tree.push_back(node); TreeNode* parent = tree[tree.size() / 2 - 1]; if (!parent->left) parent->left = node; else parent->right = node; return parent->val; }
TreeNode* get_root() { return tree[0]; }private: vector<TreeNode*> tree;};
/** * Your CBTInserter object will be instantiated and called as such: * CBTInserter* obj = new CBTInserter(root); * int param_1 = obj->insert(v); * TreeNode* param_2 = obj->get_root(); */2018 年 10 月 7 日 —— 假期最后一天!! 2018 年 12 月 11 日 —— 双十一已经过去一个月了,真快啊。。

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