# 284. Peeking Iterator 顶端迭代器

## # 题目描述：

Given an Iterator class interface with methods: `next()` and `hasNext()`, design and implement a PeekingIterator that support the `peek()` operation -- it essentially `peek()` at the element that will be returned by the next call to `next()`.

Example:

``````Assume that the iterator is initialized to the beginning of the list: [1,2,3].

Call next() gets you 1, the first element in the list.
Now you call peek() and it returns 2, the next element. Calling next() after that still return 2.
You call next() the final time and it returns 3, the last element.
Calling hasNext() after that should return false.
``````

Follow up: How would you extend your design to be generic and work with all types, not just integer?

## # 解题方法

``````# Below is the interface for Iterator, which is already defined for you.
#
# class Iterator(object):
#     def __init__(self, nums):
#         """
#         Initializes an iterator object to the beginning of a list.
#         :type nums: List[int]
#         """
#
#     def hasNext(self):
#         """
#         Returns true if the iteration has more elements.
#         :rtype: bool
#         """
#
#     def next(self):
#         """
#         Returns the next element in the iteration.
#         :rtype: int
#         """

class PeekingIterator(object):
def __init__(self, iterator):
"""
:type iterator: Iterator
"""
self.iterator = iterator
self.n = None

def peek(self):
"""
Returns the next element in the iteration without advancing the iterator.
:rtype: int
"""
if self.n == None:
self.n = self.iterator.next()
return self.n

def next(self):
"""
:rtype: int
"""
if self.n != None:
tmp = self.n
self.n = None
return tmp
else:
return self.iterator.next()

def hasNext(self):
"""
:rtype: bool
"""
if self.n != None:
return True
else:
return self.iterator.hasNext()

# Your PeekingIterator object will be instantiated and called as such:
# iter = PeekingIterator(Iterator(nums))
# while iter.hasNext():
#     val = iter.peek()   # Get the next element but not advance the iterator.
#     iter.next()         # Should return the same value as [val].
``````

## # 日期

2018 年 9 月 26 日 —— 美好的一周又快要过去了。。