# 690. Employee Importance 员工的重要性

@TOC

## # 题目描述

You are given a data structure of employee information, which includes the employee's unique id, his importance value and his direct subordinates' id.

For example, employee 1 is the leader of employee 2, and employee 2 is the leader of employee 3. They have importance value 15, 10 and 5, respectively. Then employee 1 has a data structure like [1, 15, [2]], and employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []]. Note that although employee 3 is also a subordinate of employee 1, the relationship is not direct.

Now given the employee information of a company, and an employee id, you need to return the total importance value of this employee and all his subordinates.

Example 1:

Input: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1
Output: 11
Explanation:
Employee 1 has importance value 5, and he has two direct subordinates: employee 2 and employee 3. They both have importance value 3. So the total importance value of employee 1 is 5 + 3 + 3 = 11.

Note:

1. One employee has at most one direct leader and may have several subordinates.
2. The maximum number of employees won't exceed 2000.

## # 解题方法

### # 方法一：DFS

"""
# Employee info
class Employee(object):
def __init__(self, id, importance, subordinates):
# It's the unique id of each node.
# unique id of this employee
self.id = id
# the importance value of this employee
self.importance = importance
# the id of direct subordinates
self.subordinates = subordinates
"""
class Solution(object):
def getImportance(self, employees, id):
"""
:type employees: Employee
:type id: int
:rtype: int
"""
employee_dict = {employee.id : employee for employee in employees}
def dfs(id):
return employee_dict[id].importance + sum(dfs(id) for id in employee_dict[id].subordinates)
return dfs(id)

"""
# Employee info
class Employee:
def __init__(self, id, importance, subordinates):
# It's the unique id of each node.
# unique id of this employee
self.id = id
# the importance value of this employee
self.importance = importance
# the id of direct subordinates
self.subordinates = subordinates
"""
class Solution:
def getImportance(self, employees, id):
"""
:type employees: Employee
:type id: int
:rtype: int
"""
emap = {employee.id : employee for employee in employees}
res = emap[id].importance
for sub in emap[id].subordinates:
res += self.getImportance(employees, sub)
return res

## # 日期

2018 年 1 月 17 日 2018 年 11 月 10 日 —— 这么快就到双十一了？？