# 816. Ambiguous Coordinates 模糊坐标

## # 题目描述：

We had some 2-dimensional coordinates, like `"(1, 3)"` or `"(2, 0.5)"`. Then, we removed all commas, decimal points, and spaces, and ended up with the string `S`. Return a list of strings representing all possibilities for what our original coordinates could have been.

Our original representation never had extraneous zeroes, so we never started with numbers like "00", "0.0", "0.00", "1.0", "001", "00.01", or any other number that can be represented with less digits. Also, a decimal point within a number never occurs without at least one digit occuring before it, so we never started with numbers like ".1".

The final answer list can be returned in any order. Also note that all coordinates in the final answer have exactly one space between them (occurring after the comma.)

Example 1:

``````Input: "(123)"
Output: ["(1, 23)", "(12, 3)", "(1.2, 3)", "(1, 2.3)"]
``````

Example 2:

``````Input: "(00011)"
Output:  ["(0.001, 1)", "(0, 0.011)"]
Explanation:
0.0, 00, 0001 or 00.01 are not allowed.
``````

Example 3:

``````Input: "(0123)"
Output: ["(0, 123)", "(0, 12.3)", "(0, 1.23)", "(0.1, 23)", "(0.1, 2.3)", "(0.12, 3)"]
``````

Example 4:

``````Input: "(100)"
Output: [(10, 0)]
Explanation:
1.0 is not allowed.
``````

Note:

1. 4 <= S.length <= 12.
2. S = "(", S[S.length - 1] = ")", and the other elements in S are digits.

## # 解题方法

1. 看能否组成合理整数：长度为1或者没有前导0
2. 看能否组成合理小数：把数字再次分割成整数部分和小数部分
• 整数部分可以只有1位并且为0，否则不能有前导0
• 小数部分结尾不能为0

``````class Solution(object):
def ambiguousCoordinates(self, S):
"""
:type S: str
:rtype: List[str]
"""
ans = []
S = S[1:-1]
for i in range(1, len(S)):
left, right = S[:i], S[i:]
left_list = self.get_number(left)
right_list = self.get_number(right)
if left_list and right_list:
for left_number in left_list:
for right_number in right_list:
ans.append("(" + left_number + ", " + right_number + ")")
return ans

def get_number(self, num):
decimal_list = []
if len(num) == 1 or num != '0':
decimal_list.append(num)
for i in range(1, len(num)):
integer, fractor = num[:i], num[i:]
print(integer, fractor)
if (len(integer) > 1 and integer == '0') or fractor[-1] == '0':
continue
decimal_list.append(integer + '.' + fractor)
return decimal_list
``````

## # 日期

2018 年 6 月 13 日 ———— 天阴阴，地潮潮